- 400 MPa
- 500 MPa
- 900 MPa
- 1400 MPa
- 120 dB (A)
- 130 dB (A)
- 140 dB (A)
- 115 dB (A)
- 90 dB (A)
- 85 dB (A)
Q) A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The maximum normal stress will be
Solution:
Assume stress in X direction(X) = 1200 MPa.
Stress in Y direction(Y) = 600 MPa.
Shear stress(S) = 400 MPa.
Max. Normal stress=(X+Y)/2+Sqrt(((X-Y)/2)square+S square).
= (1200+600)/2 + sqrt(300 square + 400 square).
=1400 MPa
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